The frequency of an alternating voltage is $50 \text{ cycles/sec}$ and its amplitude is $120 \text{ V}$. Then the $r.m.s.$ value of voltage is ........ $V$.

$A$ $40 \ \Omega$ electric heater is connected to a $200 \ V, 50 \ Hz$ mains supply. The peak value of electric current flowing in the circuit is approximately......$A$

The average value of an $A$.$C$. voltage given by $V = V_{m} \sin(\omega t)$ over the time interval $t = 0$ to $t = \frac{\pi}{\omega}$ is:

If ${E_0}$ represents the peak value of the voltage in an ac circuit,the r.m.s. value of the voltage will be

If the rms current in a $50 \text{ Hz}$ $AC$ circuit is $5 \text{ A}$,and at time $t=0$,the current $I$ is $0$. The value of current $I$ at $t=\frac{1}{300} \text{ s}$ is . . . . . . $A$.

An alternating current is given by the equation $i = i_{1} \sin \omega t + i_{2} \cos \omega t$. The rms current will be