The frequency of an electromagnetic radiation | vedclass

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Question

(C) The relationship between velocity of light $(c)$,frequency $(
u)$,and wavelength $(\lambda)$ is given by the formula: $c = 
u 	imes \lambda$. R

Vedclass · Accepted Answer

$1.5 	imes 10^2$

Vedclass · Answer

(C) The relationship between velocity of light $(c)$,frequency $(
u)$,and wavelength $(\lambda)$ is given by the formula: $c = 
u 	imes \lambda$. Rearranging the formula to solve for wavelength: $\lambda = \frac{c}{
u}$. Given: $c = 3 	imes 10^8 \ m \ s^{-1}$ and $
u = 2 	imes 10^6 \ Hz$. Substituting the values: $\lambda = \frac{3 	imes 10^8}{2 	imes 10^6} = 1.5 	imes 10^2 \ m$. Therefore,the correct option is $(C)$.

The frequency of an electromagnetic radiation is $2 \times 10^6 \ Hz$. What is its wavelength in metres? (Velocity of light $= 3 \times 10^8 \ m \ s^{-1}$)

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