The gas evolved when ethyl amine reacts with sodium metal is

  • A
    $NH_3$
  • B
    $N_2$
  • C
    $H_2$
  • D
    $C_2H_6$

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Similar Questions

In the following compounds,the decreasing order of basic strength will be:

The major product in the above reaction is:

Compound $III$ is
$\xrightarrow[{ii)\,CuCl/HCl}]{{i)\,HNO_2\,(0 - 5\,^oC)}}I$ $\xrightarrow{{Sn/HCl}}II$ $\xrightarrow[{ii)\,H_3PO_2 + H_2O}]{{i)HNO_2\,(0 - 5\,^oC)\,}}III$

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$Ph-NH_2$ $\xrightarrow[Br_2]{HNO_2} A$ $\xrightarrow[Warm]{H_2O} B$
$B$ is

The product$(s)$ of the following reaction sequence is(are):
Aniline $\xrightarrow[\text{ii) } KBrO_3/HBr]{\text{i) Acetic anhydride/pyridine}}$ $\xrightarrow[\text{iv) } NaNO_2/HCl, 273-278 \ K]{\text{iii) } H_3O^+, \text{heat}}$ $\xrightarrow{\text{v) } Cu/HBr} \text{Product}$

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