The general solution of tan 3x = 1 is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given the equation $	an 3x = 1$.We know that $	an \frac{\pi}{4} = 1$.Therefore,$	an 3x = 	an \frac{\pi}{4}$.The general solution for $	an 	h

Vedclass · Accepted Answer

$\frac{n\pi}{3} + \frac{\pi}{12}$

Vedclass · Answer

(B) Given the equation $	an 3x = 1$.We know that $	an \frac{\pi}{4} = 1$.Therefore,$	an 3x = 	an \frac{\pi}{4}$.The general solution for $	an 	heta = 	an \alpha$ is $	heta = n\pi + \alpha$,where $n \in \mathbb{Z}$.Applying this to our equation,we get $3x = n\pi + \frac{\pi}{4}$.Dividing both sides by $3$,we obtain $x = \frac{n\pi}{3} + \frac{\pi}{12}$.

The general solution of $\tan 3x = 1$ is

Similar Questions

If $\cos \theta + \cos 2\theta + \cos 3\theta = 0$,then the general value of $\theta$ is

If $\tan (\cot x) = \cot (\tan x),$ then $\sin 2x =$

What is the number of roots of the quadratic equation $8\sec^2\theta - 6\sec\theta + 1 = 0$?

The number of solutions of $\cos 2 \theta = \sin \theta$ in the interval $(0, 2 \pi)$ is:

If $2\sin \theta + \tan \theta = 0$,then the general values of $\theta$ are

Vedclass Test Series

Exam Paper Generator

Online Exam Module