The geometry of [Ni(CO)_4] and [NiCl_2(PPh_3) | vedclass

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Question

(C) For $[Ni(CO)_4]$: The oxidation state of $Ni$ is $0$. The configuration is $[Ar] 3d^8 4s^2$. Since $CO$ is a strong field ligand,it causes pairing

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both are tetrahedral

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(C) For $[Ni(CO)_4]$: The oxidation state of $Ni$ is $0$. The configuration is $[Ar] 3d^8 4s^2$. Since $CO$ is a strong field ligand,it causes pairing of electrons,leading to $sp^3$ hybridization. Thus,the geometry is tetrahedral.For $[NiCl_2(PPh_3)_2]$: The oxidation state of $Ni$ is $+2$. The configuration is $[Ar] 3d^8$. Both $Cl^-$ and $PPh_3$ are generally considered weak field ligands in this specific complex geometry,leading to $sp^3$ hybridization. Thus,the geometry is tetrahedral.Therefore,both complexes are tetrahedral.

The geometry of $[Ni(CO)_4]$ and $[NiCl_2(PPh_3)_2]$ are

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