The given circuit is equivalent to:

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(A) Let $p$ be the switch $S_1$ and $q$ be the switch $S_2$. The symbolic form of the given circuit is $(p \wedge \sim q) \vee (\sim p \wedge q) \vee

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(A) Let $p$ be the switch $S_1$ and $q$ be the switch $S_2$. The symbolic form of the given circuit is $(p \wedge \sim q) \vee (\sim p \wedge q) \vee (\sim p \wedge \sim q)$.Simplifying the expression:$= (p \wedge \sim q) \vee [\sim p \wedge (q \vee \sim q)]$$= (p \wedge \sim q) \vee [\sim p \wedge t]$$= (p \wedge \sim q) \vee \sim p$$= \sim p \vee (p \wedge \sim q)$$= (\sim p \vee p) \wedge (\sim p \vee \sim q)$$= t \wedge (\sim p \vee \sim q)$$= \sim p \vee \sim q$The expression $\sim p \vee \sim q$ represents two switches $S_1'$ and $S_2'$ connected in parallel.

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