The given reaction
C_6H_5-CHO + Br-CH_2-COOC | vedclass

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Question

(C) The reaction of an aldehyde or ketone with an $\alpha$-bromo ester in the presence of metallic $Zn$ followed by hydrolysis and dehydration is know

Vedclass · Accepted Answer

Reformatsky reaction

Vedclass · Answer

(C) The reaction of an aldehyde or ketone with an $\alpha$-bromo ester in the presence of metallic $Zn$ followed by hydrolysis and dehydration is known as the Reformatsky reaction.
In this reaction,an organozinc intermediate is formed,which then reacts with the carbonyl group to yield a $\beta$-hydroxy ester,which upon heating $(\Delta)$ undergoes dehydration to form an $\alpha,\beta$-unsaturated ester.
Therefore,the given reaction is the Reformatsky reaction.

The given reaction
$C_6H_5-CHO + Br-CH_2-COOC_2H_5 \xrightarrow[(ii) HOH/NH_4Cl, (iii) \Delta]{(i) Zn} C_6H_5-CH=CH-COOC_2H_5$
is known as:

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Which of the following undergoes haloform reaction?
$ (i) \ CH_3CH_2COCH_2Cl $
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$ (iv) \ CH_3CH_2COCCl_3 $

In the reaction sequence $C_6H_5-CH(OH)-CH_2-C(=O)-CH_3 \xrightarrow{(i) NaOBr, (ii) H_2O/H^{+}, (iii) \Delta}$ product,the product will be:

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The given reaction $C_6H_5-CHO + Br-CH_2-COOC_2H_5 \xrightarrow[(ii) HOH/NH_4Cl, (iii) \Delta]{(i) Zn} C_6H_5-CH=CH-COOC_2H_5$ is known as: