The graph of the equation 2x - y = 1 does not | vedclass

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(A) To determine if a point $(x, y)$ lies on the graph of the equation $2x - y = 1$,we substitute the $x$ and $y$ coordinates of the point into the eq

Vedclass · Accepted Answer

$(0, 0)$

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(A) To determine if a point $(x, y)$ lies on the graph of the equation $2x - y = 1$,we substitute the $x$ and $y$ coordinates of the point into the equation.If the left-hand side equals the right-hand side,the point lies on the graph.$A) (0, 0): 2(0) - 0 = 0 
eq 1$. Thus,the graph does not pass through $(0, 0)$.$B) (1, 1): 2(1) - 1 = 2 - 1 = 1$. The graph passes through $(1, 1)$.$C) (3, 5): 2(3) - 5 = 6 - 5 = 1$. The graph passes through $(3, 5)$.$D) (2, 3): 2(2) - 3 = 4 - 3 = 1$. The graph passes through $(2, 3)$.Therefore,the graph does not pass through $(0, 0)$.

The graph of the equation $2x - y = 1$ does not pass through which of the following points?

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