The graph between u and v for a convex mirror | vedclass

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(B) For a convex mirror,the mirror formula is given by $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$.Since the focal length $f$ is positive for a convex m

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(B) For a convex mirror,the mirror formula is given by $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$.Since the focal length $f$ is positive for a convex mirror,we have $\frac{1}{v} = \frac{1}{f} - \frac{1}{u}$.Using sign convention,$u$ is negative,so let $u = -x$ where $x > 0$. Then $\frac{1}{v} = \frac{1}{f} + \frac{1}{x} = \frac{x+f}{xf}$.Thus,$v = \frac{xf}{x+f}$.As $u$ varies from $0$ to $-\infty$,$x$ varies from $0$ to $+\infty$.When $x = 0$,$v = 0$.When $x 	o \infty$,$v 	o f$.As $x$ increases,$v$ increases from $0$ to $f$. The graph shows $v$ on the $y$-axis and $u$ on the $x$-axis (where $u$ is negative). The correct representation is Graph $B$.

The graph between $u$ and $v$ for a convex mirror is

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