The graph between two temperature scales P an | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The general formula for converting between two temperature scales is given by:$\frac{	ext{Reading on scale} - 	ext{Lower fixed point}}{	ext{Upp

Vedclass · Accepted Answer

$\frac{t_Q}{100}=\frac{t_P-30}{150}$

Vedclass · Answer

(B) The general formula for converting between two temperature scales is given by:$\frac{	ext{Reading on scale} - 	ext{Lower fixed point}}{	ext{Upper fixed point} - 	ext{Lower fixed point}} = 	ext{Constant}$From the graph,for scale $P$,the lower fixed point is $30$ and the upper fixed point is $180$ (since $180 - 30 = 150$ divisions).For scale $Q$,the lower fixed point is $0$ and the upper fixed point is $100$ (since $100 - 0 = 100$ divisions).Applying the formula:$\frac{t_P - 30}{180 - 30} = \frac{t_Q - 0}{100 - 0}$Simplifying the expression:$\frac{t_P - 30}{150} = \frac{t_Q}{100}$

The graph between two temperature scales $P$ and $Q$ is shown in the figure. Between the upper fixed point and the lower fixed point,there are $150$ equal divisions on scale $P$ and $100$ divisions on scale $Q$. The relationship for conversion between the two scales is given by:

Similar Questions

Two thermometers are used to record the temperature of a room. If the bulb of one is wrapped in a wet hanky,which of the following statements is correct?

If the reading in Fahrenheit scale is twice the reading in Celsius scale, then the reading in Fahrenheit scale is (in $^{\circ} F$)

If the temperature of an object is $140^{\circ}F$,then its temperature in Celsius is ........ $^{\circ}C$.

$Assertion :$ Fahrenheit is the smallest unit measuring temperature.
$Reason :$ Fahrenheit was the first temperature scale used for measuring temperature.

On a linear temperature scale $Y$,water freezes at $-160^{\circ}Y$ and boils at $-50^{\circ}Y$. On this $Y$ scale,a temperature of $340\,K$ would be read as........ $^{\circ}Y$ (water freezes at $273\,K$ and boils at $373\,K$).

Vedclass Test Series

Exam Paper Generator

Online Exam Module