(C) To find the points where the graph of $p(x) = x^2 - 9$ intersects the $X$-axis,we set $p(x) = 0$.$x^2 - 9 = 0$$(x - 3)(x + 3) = 0$This gives $x =

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(C) To find the points where the graph of $p(x) = x^2 - 9$ intersects the $X$-axis,we set $p(x) = 0$.$x^2 - 9 = 0$$(x - 3)(x + 3) = 0$This gives $x = 3$ and $x = -3$.Since there are two distinct real roots,the graph intersects the $X$-axis at two distinct points: $(3, 0)$ and $(-3, 0)$.Therefore,the correct option is $C$.

Class 10 Mathematics Polynomials Geometrical Meaning of the Zeroes of a Polynomial

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The graph of $p(x) = x^2 - 9$ intersects the $X$-axis in .......... distinct points.

A
$0$
B
$1$
C
$2$
D
$3$

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Geometrical Meaning of the Zeroes of a Polynomial

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The graph of $p(x) = x^2 - 9$ intersects the $X$-axis in .......... distinct points.

Similar Questions

The graph of $p(x) = x^{2} + 6x + 8$ is a ........

The graph of linear polynomial $p(x) = 3x - 6$ intersects the $X$-axis at $\ldots......$

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The number of real zeros of $y=p(x)$ is ............... in the given figure.

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