The graph of the equation ldots ldots ldots l | vedclass

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(C) line perpendicular to the $X$-axis is a vertical line,which is represented by the equation of the form $x = k$,where $k$ is a constant.In the give

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$3x + 2 = 0$

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(C) line perpendicular to the $X$-axis is a vertical line,which is represented by the equation of the form $x = k$,where $k$ is a constant.In the given options:$A) x - y = 0 \implies y = x$ (a line passing through the origin with slope $1$)$B) x + y = 0 \implies y = -x$ (a line passing through the origin with slope $-1$)$C) 3x + 2 = 0 \implies 3x = -2 \implies x = -2/3$ (this is a vertical line,perpendicular to the $X$-axis)$D) 2y - 3 = 0 \implies 2y = 3 \implies y = 3/2$ (this is a horizontal line,parallel to the $X$-axis)Therefore,the correct option is $C$.

The graph of the equation $\ldots \ldots \ldots \ldots$ is a line perpendicular to the $X$-axis.

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