The graph of maximum kinetic energy (K.E._{ma | vedclass

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(A) According to Einstein's photoelectric equation,the maximum kinetic energy $(K.E._{max})$ of emitted photoelectrons is given by:$K.E._{max} = h
u

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Planck's constant,threshold frequency

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(A) According to Einstein's photoelectric equation,the maximum kinetic energy $(K.E._{max})$ of emitted photoelectrons is given by:$K.E._{max} = h
u - \phi_0$Comparing this with the equation of a straight line $y = mx + c$,where $y = K.E._{max}$ and $x = 
u$:$1$. The slope $(m)$ of the graph is equal to Planck's constant $(h)$.$2$. The $X$-axis intercept occurs when $K.E._{max} = 0$,which gives $0 = h
u_0 - \phi_0$,or $
u_0 = \phi_0 / h$. This intercept represents the threshold frequency $(
u_0)$.Therefore,the slope is Planck's constant and the $X$-axis intercept is the threshold frequency.

The graph of maximum kinetic energy $(K.E._{max})$ against the frequency $(\nu)$ of incident light is as shown in the figure. The slope of the graph and the intercept on the $X$-axis respectively are:

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