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(C) The graph between applied force $(F)$ and extension $(x)$ is a straight line because,according to Hooke's law,$F = kx$,which implies $F \propto x$

Vedclass · Accepted Answer

$P =$ extension,$Q =$ stored elastic energy

Vedclass · Answer

(C) The graph between applied force $(F)$ and extension $(x)$ is a straight line because,according to Hooke's law,$F = kx$,which implies $F \propto x$.However,the graph between extension $(x)$ and stored elastic potential energy $(U)$ is parabolic in nature.The formula for stored elastic potential energy is $U = \frac{1}{2} k x^2$,which implies $U \propto x^2$.Since the given graph is parabolic,$P$ must represent the extension $(x)$ and $Q$ must represent the stored elastic energy $(U)$.

The graph shows the behavior of a length of wire in the region for which the substance obeys Hooke's law. $P$ and $Q$ represent:

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