The half-life of a zero-order reaction is $1 \text{ hour}$. If the initial concentration of the reactant is $2.0 \text{ mol L}^{-1}$, find the time required to decrease the concentration from $0.50 \text{ mol L}^{-1}$ to $0.25 \text{ mol L}^{-1}$. (in $\text{ hour}$)

  • A
    $0.25$
  • B
    $0.50$
  • C
    $0.75$
  • D
    $1.00$

Explore More

Similar Questions

In a zero-order reaction,if the initial concentration of the reactant is doubled,the time required for half the reactant to be consumed:

The order of reaction for which the units of rate constant are $mol \ dm^{-3} \ s^{-1}$ is

The reaction $A \to \text{Products}$ is a zero-order reaction. If the initial concentration of $A$ is $2 \ M$,then at time $t = 1/K$ (where $K$ is the rate constant),the concentration of $A$ will be ......... $M$.

Which of the following is the incorrect equation for the rate constant of a zero-order reaction?

The rate constant,$k$ of a zero order reaction $2 NH_{3(g)} \xrightarrow[1130 \ K]{Pt} N_{2(g)} + 3 H_{2(g)}$ is $y \times 10^{-4} \ mol \ L^{-1} \ s^{-1}$. The rate of formation of hydrogen (in $mol \ L^{-1} \ s^{-1}$) is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo