The heat generated in 1 text{ minute} between | vedclass

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Question

(B) The circuit is a balanced Wheatstone bridge because the ratio of resistances in the arms is $\frac{1}{2} = \frac{2}{4}$.Therefore, no current flow

Vedclass · Accepted Answer

$1080$

Vedclass · Answer

(B) The circuit is a balanced Wheatstone bridge because the ratio of resistances in the arms is $\frac{1}{2} = \frac{2}{4}$.Therefore, no current flows through the central $1 \ \Omega$ resistor.The equivalent resistance of the upper branch is $1 + 2 = 3 \ \Omega$.The equivalent resistance of the lower branch is $2 + 4 = 6 \ \Omega$.The equivalent resistance $R_{AB}$ of the parallel combination is $\frac{3 	imes 6}{3 + 6} = \frac{18}{9} = 2 \ \Omega$.The total resistance of the circuit including the internal resistance $r = 1 \ \Omega$ is $R_{total} = R_{AB} + r = 2 + 1 = 3 \ \Omega$.The total current drawn from the battery is $i = \frac{V}{R_{total}} = \frac{9}{3} = 3 	ext{ A}$.The heat generated between points $A$ and $B$ is given by $H = i^2 R_{AB} t$, where $t = 60 	ext{ s}$.$H = (3)^2 	imes 2 	imes 60 = 9 	imes 2 	imes 60 = 1080 	ext{ J}$.

The heat generated in $1 \text{ minute}$ between points $A$ and $B$ in the given circuit, when a battery of $9 \text{ V}$ with internal resistance of $1 \ \Omega$ is connected across these points, is . . . . . . $J$.

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