The heat of combustion of solid benzoic acid | vedclass

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(C) The combustion reaction for benzoic acid is: $C_6H_5COOH_{(s)} + \frac{15}{2}O_{2(g)} \rightarrow 7CO_{2(g)} + 3H_2O_{(l)}$.The change in the numb

Vedclass · Accepted Answer

$-321.30 - 150 R$

Vedclass · Answer

(C) The combustion reaction for benzoic acid is: $C_6H_5COOH_{(s)} + \frac{15}{2}O_{2(g)} ightarrow 7CO_{2(g)} + 3H_2O_{(l)}$.The change in the number of gaseous moles is $\Delta n_g = n_p(g) - n_r(g) = 7 - 7.5 = -0.5$.The relationship between enthalpy change and internal energy change is $\Delta H = \Delta U + \Delta n_g RT$.Given $\Delta U = -321.30 \ kJ$,$T = 27 + 273 = 300 \ K$,and $\Delta n_g = -0.5$.Substituting the values: $\Delta H = -321.30 + (-0.5 	imes R 	imes 300) = -321.30 - 150 R$.

The heat of combustion of solid benzoic acid at constant volume is $-321.30 \ kJ$ at $27^{\circ} C$. Its heat of combustion at constant pressure is :

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