The height at which the acceleration due to gravity becomes $\frac{g}{9}$ (where $g$ = the acceleration due to gravity on the surface of the earth) in terms of $R$,the radius of the earth,is

  • A
    $2R$
  • B
    $\frac{R}{\sqrt{2}}$
  • C
    $\frac{R}{2}$
  • D
    $\sqrt{2}R$

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