The highest oxidation state of manganese in f | vedclass

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(D) Step $1$: Manganese can exhibit a maximum oxidation state of $+7$ by using all its valence electrons $(3d^5 4s^2)$.Step $2$: Oxygen has the unique

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In covalent compounds, fluorine can form single bond only, while oxygen forms double bond

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(D) Step $1$: Manganese can exhibit a maximum oxidation state of $+7$ by using all its valence electrons $(3d^5 4s^2)$.Step $2$: Oxygen has the unique ability to form multiple bonds (specifically $p\pi - d\pi$ multiple bonds) with transition metals, which stabilizes the higher oxidation states of the metal.Step $3$: Fluorine, being highly electronegative and small, can only form single covalent bonds $(Mn-F)$. It cannot form multiple bonds with manganese.Step $4$: Therefore, oxygen can satisfy the high valency of manganese in $Mn_2O_7$ through multiple bonding, whereas fluorine is restricted to $MnF_4$.

The highest oxidation state of manganese in fluorides is $+4$ $(MnF_4)$, but the highest oxidation state in oxides is $+7$ $(Mn_2O_7)$, because

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