The horizontal component of the earth's magnetic field at a place is $3 \times 10^{-4} \, T$ and the angle of dip is $53^\circ$. $A$ metal rod of length $0.25 \, m$ is placed in the north-south position and is moved at a constant speed of $10 \, cm/s$ towards the east. The emf induced in the rod will be ...... $\mu V$. (Given $\tan 53^\circ = 4/3$)

  • A
    $0$
  • B
    $1$
  • C
    $5$
  • D
    $10$

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