The huge amount of energy which is released during atomic fission is due to

  • A
    Loss of mass
  • B
    Loss of electrons
  • C
    Loss of protons
  • D
    Loss of $\alpha$-particles

Explore More

Similar Questions

Hydrogen can be fused to form helium at

During the emission of a positron from a nucleus, the mass number of the daughter element remains the same but the atomic number

Let $m_p$ be the mass of a proton,$m_n$ that of a neutron,$M_1$ that of a $_{10}^{20}Ne$ nucleus,and $M_2$ that of a $_{20}^{40}Ca$ nucleus. Then:

When a radioactive substance is subjected to vacuum,the rate of disintegration per second

If the binding energy per nucleon of $_1H^2$ is $x$ and that of $_2He^4$ is $7x$,then the ratio of the energy liberated in the reaction $_1H^2 + _1H^2 \to _2He^4$ to the binding energy per nucleon of $_1H^2$ is:

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo