The hybridisation in BF_3 molecule is | vedclass

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(B) In the $BF_3$ molecule,the central Boron atom has $3$ valence electrons. It forms $3$ single bonds with $3$ Fluorine atoms. Using the formula for

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$sp^2$

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(B) In the $BF_3$ molecule,the central Boron atom has $3$ valence electrons. It forms $3$ single bonds with $3$ Fluorine atoms. Using the formula for steric number: $	ext{Steric Number} = \frac{1}{2} 	imes (V + M - C + A)$,where $V = 3$ (valence electrons of $B$),$M = 3$ (monovalent atoms),$C = 0$,and $A = 0$. $	ext{Steric Number} = \frac{1}{2} 	imes (3 + 3) = 3$. $A$ steric number of $3$ corresponds to $sp^2$ hybridisation.

The hybridisation in $BF_3$ molecule is

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