The hybridisation of the central atom in NF_3 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In $NF_3$, the central nitrogen atom is bonded to three fluorine atoms by three $\sigma$-bonds and has one lone pair of electrons. To calculate th

Vedclass · Accepted Answer

$sp^3$

Vedclass · Answer

(A) In $NF_3$, the central nitrogen atom is bonded to three fluorine atoms by three $\sigma$-bonds and has one lone pair of electrons. To calculate the hybridisation, we use the formula: $	ext{Steric Number} = 	ext{Number of } \sigma 	ext{-bonds} + 	ext{Number of lone pairs}$. $	ext{Steric Number} = 3 + 1 = 4$. $A$ steric number of $4$ corresponds to $sp^3$ hybridisation.

The hybridisation of the central atom in $NF_3$ is:

Similar Questions

Among the following transformations,the hybridisation of the central atom remains unchanged in

Which one of the following statements is true for the ammonium ion $(NH_4^+)$?

In compound $X$,all the bond angles are exactly $109^o 28'$,$X$ is

The hybridization of atomic orbitals of nitrogen in $NO_2^+$,$NO_3^-$,and $NH_4^+$ are:

Explain the geometry of $SF_{6}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module