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(C) $1$. The oxidation state of $Co$ in $[Co(NH_3)_6]^{3+}$ is $+3$.$2$. The electronic configuration of $Co^{3+}$ is $[Ar] 3d^6$.$3$. $NH_3$ is a str

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$d^2sp^3$ and diamagnetic

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(C) $1$. The oxidation state of $Co$ in $[Co(NH_3)_6]^{3+}$ is $+3$.$2$. The electronic configuration of $Co^{3+}$ is $[Ar] 3d^6$.$3$. $NH_3$ is a strong field ligand,which causes pairing of electrons in the $3d$ orbitals.$4$. After pairing,the $3d$ orbitals have two vacant $d$-orbitals,one $4s$ orbital,and three $4p$ orbitals available for hybridization.$5$. This results in $d^2sp^3$ hybridization,which is inner orbital octahedral geometry.$6$. Since all electrons are paired in the $3d$ orbitals,the complex is diamagnetic.

List-$I$ (Complexes)	List-$II$ (Hybridisation)
$A$. $[Ni(CO)_4]$	$I$. $sp^3$
$B$. $[Cu(NH_3)_4]^{2+}$	$II$. $dsp^2$
$C$. $[Fe(NH_3)_6]^{2+}$	$III$. $sp^3d^2$
$D$. $[Fe(H_2O)_6]^{2+}$	$IV$. $d^2sp^3$

The hybridization and magnetic behaviour of the cobalt ion in the $[Co(NH_3)_6]^{3+}$ complex,respectively,are:

Similar Questions

Match List-$I$ with List-$II$:

List-$I$ (Complexes) List-$II$ (Hybridisation)

$A$. $[Ni(CO)_4]$ $I$. $sp^3$

$B$. $[Cu(NH_3)_4]^{2+}$ $II$. $dsp^2$

$C$. $[Fe(NH_3)_6]^{2+}$ $III$. $sp^3d^2$

$D$. $[Fe(H_2O)_6]^{2+}$ $IV$. $d^2sp^3$

Which of the following pairs of complex compounds are both tetrahedral and diamagnetic?

In an octahedral structure,which pair of $d$-orbitals is involved in ${d^2}sp^3$ hybridization?

For $K_3[Co(CN)_6]$,which of the following statements is not correct?

The geometries of the ammonia complexes of $Ni^{2+}$,$Pt^{2+}$ and $Zn^{2+}$,respectively,are

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