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(C) The structure of the molecule is $CH_1 \equiv C_2 - C_3H = C_4H_2$.$C_1$ is $sp$ hybridized.$C_2$ is $sp$ hybridized because it is attached to a t

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$sp-sp^2$

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(C) The structure of the molecule is $CH_1 \equiv C_2 - C_3H = C_4H_2$.$C_1$ is $sp$ hybridized.$C_2$ is $sp$ hybridized because it is attached to a triple bond.$C_3$ is $sp^2$ hybridized because it is attached to a double bond.$C_4$ is $sp^2$ hybridized.The bond between $C_2$ and $C_3$ involves the overlap of an $sp$ orbital from $C_2$ and an $sp^2$ orbital from $C_3$.Therefore,the hybridization of the $C_2-C_3$ bond is $sp-sp^2$.

The hybridization of carbon involved in the $C_2-C_3$ single bond in the molecule $CH \equiv C-CH=CH_2$ is

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