The hybridizations of the central atom in the molecules $BF_3, BeF_2, BrF_3$ are respectively
- A$sp^2, sp, sp^3d$
- B$sp, sp^2, sp^3$
- C$sp^3, sp, sp^3d$
- D$sp^2, sp^3, dsp^2$
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Similar Questions
What is the hybridization of $C$ atoms in graphite?
Easy
View SolutionIs there any change in the hybridization of $B$ and $N$ atoms as a result of the following reaction? $BF_3 + NH_3 \to F_3B \cdot NH_3$
Medium
View SolutionIdentify the correct set from the following table:
Molecule Hybridisation of central atom Shape $(a)$ $PCl_5$ $dsp^3$ square pyramidal $(b)$ $[Ni(CN)_4]^{2-}$ $sp^3$ tetrahedral $(c)$ $SF_6$ $sp^3d^2$ octahedral $(d)$ $IF_3$ $dsp^3$ pyramidal
| Molecule | Hybridisation of central atom | Shape |
|---|---|---|
| $(a)$ $PCl_5$ | $dsp^3$ | square pyramidal |
| $(b)$ $[Ni(CN)_4]^{2-}$ | $sp^3$ | tetrahedral |
| $(c)$ $SF_6$ | $sp^3d^2$ | octahedral |
| $(d)$ $IF_3$ | $dsp^3$ | pyramidal |
Explain the bond formation by $sp$ orbitals.
Medium
View SolutionWhat is the hybridization state of the central atom in the conjugate base of $NH_4^{+}$ ion?
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