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(B) For a convex mirror,the magnification $m$ is given by $m = -v/u$. Given that the image size is one-third of the object size,$m = 1/3$.Since $m = -

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$8 \, cm$ behind the mirror

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(B) For a convex mirror,the magnification $m$ is given by $m = -v/u$. Given that the image size is one-third of the object size,$m = 1/3$.Since $m = -v/u = 1/3$,we have $u = -3v$.The mirror formula is $1/f = 1/v + 1/u$.Given $f = +12 \, cm$ (for a convex mirror),we substitute the values: $1/12 = 1/v + 1/(-3v)$.$1/12 = (3 - 1) / 3v = 2 / 3v$.$3v = 24$,which gives $v = +8 \, cm$.$A$ positive value for $v$ indicates that the image is formed $8 \, cm$ behind the mirror.

The image formed by a convex mirror is only one-third of the size of the object. If the focal length of the mirror is $12 \, cm$,the image formed will be

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