The incorrect statement in respect of the chr | vedclass

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Question

(D) The chromyl chloride test is used for the detection of $Cl^-$ ions. In this test,$4NaCl + K_2Cr_2O_7 + 3H_2SO_4 \longrightarrow K_2SO_4 + 2Na_2SO_

Vedclass · Accepted Answer

liberation of chlorine

Vedclass · Answer

(D) The chromyl chloride test is used for the detection of $Cl^-$ ions. In this test,$4NaCl + K_2Cr_2O_7 + 3H_2SO_4 \longrightarrow K_2SO_4 + 2Na_2SO_4 + 2CrO_2Cl_2 \uparrow + 3H_2O$. The $CrO_2Cl_2$ (chromyl chloride) formed appears as reddish-brown vapours. When these vapours are passed into $NaOH$ solution,it forms sodium chromate: $CrO_2Cl_2 + 4NaOH \longrightarrow 2NaCl + Na_2CrO_4 + 2H_2O$. This solution,when treated with lead acetate,gives a yellow precipitate of lead chromate: $Na_2CrO_4 + (CH_3COO)_2Pb \longrightarrow 2CH_3COONa + PbCrO_4 \downarrow$. Chlorine gas is not liberated in this test. Therefore,the statement 'liberation of chlorine' is incorrect.

The incorrect statement in respect of the chromyl chloride test is:

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