The incorrect statement regarding X in the gi | vedclass

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Question

(C) The reaction of boron trifluoride with lithium aluminium hydride in diethyl ether produces diborane $(B_2H_6)$:$4BF_3 + 3LiAlH_4 \rightarrow 2B_2H

Vedclass · Accepted Answer

$X$ does not react with $NH_3$

Vedclass · Answer

(C) The reaction of boron trifluoride with lithium aluminium hydride in diethyl ether produces diborane $(B_2H_6)$:$4BF_3 + 3LiAlH_4 ightarrow 2B_2H_6 + 3LiF + 3AlF_3$Thus,$X$ is diborane $(B_2H_6)$.Structure of diborane $(B_2H_6)$:$1$. It contains four $2$-centre-$2$-electron $(2c-2e)$ bonds (terminal $B-H$ bonds).$2$. It contains two $3$-centre-$2$-electron $(3c-2e)$ bonds (bridging $B-H-B$ bonds).$3$. Total electrons involved in bonding: $4 	imes 2$ (terminal) $+ 2 	imes 2$ (bridging) $= 12$ electrons.$4$. Diborane reacts with $NH_3$ to form various products such as borazine $(B_3N_3H_6)$ or the ionic compound $[H_2B(NH_3)_2]^+[BH_4]^-$.Therefore,the statement that $X$ does not react with $NH_3$ is incorrect.

The incorrect statement regarding $X$ in the given reaction is:
$BF_3 + LiAlH_4 \xrightarrow{\text{Ether}} X + LiF + AlF_3$

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The incorrect statement regarding $X$ in the given reaction is:$BF_3 + LiAlH_4 \xrightarrow{\text{Ether}} X + LiF + AlF_3$