The incorrect statement regarding $O(SiH_3)_2$ and $OCl_2$ molecules is/are:

In which of the following pairs of species is the bond length as well as the bond energy of the $I^{st}$ species less than the $II^{nd}$ species?

Which of the following statements is true with respect to $H_2O$,$NH_3$ and $CH_4$?
$A.$ The central atoms of all the molecules are $sp^3$ hybridized.
$B.$ The $H-O-H$,$H-N-H$ and $H-C-H$ angles in the above molecules are $104.5^{\circ}$,$107.5^{\circ}$ and $109.5^{\circ}$ respectively.
$C.$ The increasing order of dipole moment is $CH_4 < NH_3 < H_2O$.
$D.$ Both $H_2O$ and $NH_3$ are Lewis acids and $CH_4$ is a Lewis base.
$E.$ $A$ solution of $NH_3$ in $H_2O$ is basic. In this solution,$NH_3$ and $H_2O$ act as a Lowry-Bronsted base and acid respectively.
Choose the correct answer from the options given below:

Which of the following molecules is theoretically not possible?

Which of the following is the correct decreasing order of bond angles?

In which of the following options, the order of arrangement does not agree with the variation of property indicated against it?
$(a)$ $BF_3 < NF_3 < NH_3$ (Dipole moment)
$(b)$ $HgCl_2 > NH_4^+ > SF_6$ (Bond angle)