The increasing order (lowest first) for the v | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The $e/m$ ratio (specific charge) is calculated as follows:$(I)$ For neutron $(n)$: Charge = $0$,Mass = $1$,so $e/m = 0/1 = 0$.$(II)$ For $\alpha$

Vedclass · Accepted Answer

$n, \alpha, p, e$

Vedclass · Answer

(D) The $e/m$ ratio (specific charge) is calculated as follows:$(I)$ For neutron $(n)$: Charge = $0$,Mass = $1$,so $e/m = 0/1 = 0$.$(II)$ For $\alpha$-particle $(\alpha)$: Charge = $ 2$,Mass = $4$,so $e/m = 2/4 = 0.5$.$(III)$ For proton $(p)$: Charge = $ 1$,Mass = $1$,so $e/m = 1/1 = 1$.$(IV)$ For electron $(e)$: Charge = $-1$,Mass = $1/1837$,so $e/m = 1/(1/1837) = 1837$.Comparing these values: $0 Therefore,the increasing order is $n < \alpha < p < e$.

The increasing order (lowest first) for the values of $e/m$ (charge/mass) for:

Similar Questions

Which of the following statements is incorrect regarding cathode rays?

Rutherford's scattering experiment is related to the size of the

The penetration power of a proton is:

Rutherford's $\alpha$-particle scattering experiment is related to the size of the .....

Who discovered the charge of an electron? State the charge and mass of an electron.

Vedclass Test Series

Exam Paper Generator

Online Exam Module