The increasing order for the values of e/m (t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The $e/m$ ratio is defined as the charge-to-mass ratio of a particle.For a neutron $(n)$,the charge is $0$,so $e/m = 0$.For an alpha particle $(\a

Vedclass · Accepted Answer

$n, \alpha, p, e$

Vedclass · Answer

(D) The $e/m$ ratio is defined as the charge-to-mass ratio of a particle.For a neutron $(n)$,the charge is $0$,so $e/m = 0$.For an alpha particle $(\alpha)$,the charge is $+2$ and the mass is $4 \ amu$,so $e/m = 2/4 = 0.5$.For a proton $(p)$,the charge is $+1$ and the mass is $1 \ amu$,so $e/m = 1/1 = 1$.For an electron $(e^-)$,the charge is $-1$ and the mass is $1/1837 \ amu$,so $e/m = 1 / (1/1837) = 1837$.Comparing these values: $0 Thus,the increasing order is $n < \alpha < p < e$.

The increasing order for the values of $e/m$ $(\text{charge/mass})$ is :

Similar Questions

$A$ particle having the same charge and $200$ times greater mass than that of an electron is:

The fundamental particles present in the nucleus of an atom are

Write down the results of the cathode ray discharge tube experiment.

The fact that the atom is divisible was determined from ............ .

The ratio of charge to mass ($e/m$ ratio) is greatest for which of the following particles?

Vedclass Test Series

Exam Paper Generator

Online Exam Module