The increasing order of electron affinity for | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) First,identify the elements based on their electronic configurations:$I. 1s^2 2s^2 2p^6 3s^2 3p^5$ is Chlorine $(Cl)$,which has a high electron af

Vedclass · Accepted Answer

$II < IV < III < I$

Vedclass · Answer

(A) First,identify the elements based on their electronic configurations:$I. 1s^2 2s^2 2p^6 3s^2 3p^5$ is Chlorine $(Cl)$,which has a high electron affinity.$II. 1s^2 2s^2 2p^3$ is Nitrogen $(N)$,which has a half-filled $p$-orbital,making it very stable and resulting in a very low (near zero) electron affinity.$III. 1s^2 2s^2 2p^5$ is Fluorine $(F)$. Although $F$ is more electronegative than $Cl$,its electron affinity is slightly lower than $Cl$ due to high inter-electronic repulsion in the small $2p$ subshell.$IV. 1s^2 2s^2 2p^6 3s^1$ is Sodium $(Na)$,which is an alkali metal with a low electron affinity,but higher than Nitrogen $(N)$ because it can form a stable $3s^2$ configuration.Comparing these: Nitrogen $(II)$ has the lowest electron affinity due to its stable half-filled configuration. Sodium $(IV)$ is next. Fluorine $(III)$ is higher than Sodium,and Chlorine $(I)$ has the highest electron affinity among these.Therefore,the increasing order is $II < IV < III < I$.

The increasing order of electron affinity for the given electronic configurations of elements is:
$I. 1s^2 2s^2 2p^6 3s^2 3p^5$
$II. 1s^2 2s^2 2p^3$
$III. 1s^2 2s^2 2p^5$
$IV. 1s^2 2s^2 2p^6 3s^1$

Similar Questions

Which of the following pairs of elements would have a more negative electron gain enthalpy?
$(i)$ $O$ or $F$
$(ii)$ $F$ or $Cl$

Explain the periodicity of electron gain enthalpy of elements in the periodic table.

Within each pair of elements of $F$ and $Cl$,$S$ and $Se$,and $Li$ and $Na$,respectively,the elements that release more energy upon an electron gain are

Which of the following has the least electron affinity in $kJ\,mol^{-1}$?

The increasing order of electron affinity for the given electronic configurations of elements is:
$I$. $1s^2 \ 2s^2 \ 2p^6 \ 3s^2 \ 3p^5$ $(Cl)$
$II$. $1s^2 \ 2s^2 \ 2p^3$ $(N)$
$III$. $1s^2 \ 2s^2 \ 2p^5$ $(F)$
$IV$. $1s^2 \ 2s^2 \ 2p^6 \ 3s^2 \ 3p^1$ $(Al)$

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The increasing order of electron affinity for the given electronic configurations of elements is:$I. 1s^2 2s^2 2p^6 3s^2 3p^5$$II. 1s^2 2s^2 2p^3$$III. 1s^2 2s^2 2p^5$$IV. 1s^2 2s^2 2p^6 3s^1$