The increasing order of reduction of alkyl halides with zinc and dil. $HCl$ is:

Arrange the following in their correct order of reactivity towards ${S_N}^1$ reaction.

For the compounds $CH_3Cl$,$CH_3Br$,$CH_3I$,and $CH_3F$,the correct order of increasing $C$-halogen bond length is

For the following compounds,the correct statement$(s)$ with respect to nucleophilic substitution reactions is(are):
$I$: Benzyl bromide $(C_6H_5CH_2Br)$
$II$: Cyclohexylmethyl bromide $(C_6H_{11}CH_2Br)$
$III$: tert-Butyl bromide $((CH_3)_3CBr)$
$IV$: $1-$Phenylethyl bromide $(C_6H_5CH(CH_3)Br)$
$A$. $I$ and $III$ follow $S_{N}1$ mechanism
$B$. $I$ and $II$ follow $S_{N}2$ mechanism
$C$. Compound $IV$ undergoes inversion of configuration
$D$. The order of reactivity for $I$,$III$ and $IV$ is: $IV > I > III$

Which of the following is most reactive toward $S_N2$ reaction?

Which describes the best stereochemical aspects of the following reaction?
$Ph-C(CH_3)(CD_3)(OH) + HBr \rightarrow \text{Product}$