The increasing order of stability of the foll | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The stability of free radicals is governed by resonance and inductive effects.$1$. Resonance stabilization: The triphenylmethyl radical $(C_6H_5)_

Vedclass · Accepted Answer

$(CH_3)_2\dot{C}H < (CH_3)_3\dot{C} < (C_6H_5)_2\dot{C}H < (C_6H_5)_3\dot{C}$

Vedclass · Answer

(B) The stability of free radicals is governed by resonance and inductive effects.$1$. Resonance stabilization: The triphenylmethyl radical $(C_6H_5)_3\dot{C}$ is more stable than the diphenylmethyl radical $(C_6H_5)_2\dot{C}H$ because it has more phenyl groups to delocalize the unpaired electron.$2$. Inductive effect: Alkyl radicals are stabilized by the $+I$ effect of alkyl groups. The tertiary butyl radical $(CH_3)_3\dot{C}$ is more stable than the isopropyl radical $(CH_3)_2\dot{C}H$.$3$. Overall order: Resonance-stabilized radicals are significantly more stable than alkyl radicals.Therefore,the increasing order of stability is: $(CH_3)_2\dot{C}H < (CH_3)_3\dot{C} < (C_6H_5)_2\dot{C}H < (C_6H_5)_3\dot{C}$.

The increasing order of stability of the following free radicals is:

Similar Questions

The orbital picture of a singlet carbene $(:CH_2)$ can be drawn as:

Homolytic fission of $C-C$ bond in ethane gives an intermediate in which carbon is

Arrange the following carbanions in the decreasing order of their stability: ${(CH_3)_3}C^-$,$CCl_3^-$,${(CH_3)_2}CH^-$,${C_6H_5}CH_2^-$.

What is the minimum energy required for the homolytic bond fission of the $C-H$ bond in the following molecule?

The total number of electrons around the carbon atom of a methyl free radical is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module