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(B) The reactions are as follows:$(a)$ $CH_2=CH-CH_2-CH_3 + HBr \xrightarrow{Peroxide} CH_2Br-CH_2-CH_2-CH_3$ (Product $A$,$1$-bromobutane,Boiling Poi

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$B < C < A$

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(B) The reactions are as follows:$(a)$ $CH_2=CH-CH_2-CH_3 + HBr \xrightarrow{Peroxide} CH_2Br-CH_2-CH_2-CH_3$ (Product $A$,$1$-bromobutane,Boiling Point $\approx 102 \ ^\circ C$)$(b)$ $CH_2=C(CH_3)_2 + HBr \rightarrow CH_3-C(Br)(CH_3)_2$ (Product $B$,$2$-bromo-$2$-methylpropane,Boiling Point $\approx 73.3 \ ^\circ C$)$(c)$ $CH_2=CH-CH_2-CH_3 + HBr \rightarrow CH_3-CH(Br)-CH_2-CH_3$ (Product $C$,$2$-bromobutane,Boiling Point $\approx 91 \ ^\circ C$)Boiling point is inversely proportional to branching in the carbon chain.Comparing the structures: $A$ is a straight-chain primary alkyl halide,$C$ is a secondary alkyl halide with less branching than $B$,and $B$ is a tertiary alkyl halide with the most branching.Therefore,the order of boiling points is $B < C < A$.

The increasing order of the boiling points of the major products $A$,$B$ and $C$ of the following reactions will be:

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