The inductive reactance of a coil is $R \ \Omega$. If the inductance of the coil is tripled and the frequency of the $A.C.$ supply is also tripled,then the new inductive reactance will be:

An $a.c.$ source of voltage $V$ and frequency $50\,Hz$ is connected to an inductor of $2\,H$ and negligible resistance. $A$ current of $r.m.s.$ value $I$ flows in the coil. When the frequency of the voltage is changed to $400\,Hz$ keeping the magnitude of $V$ the same,the current is now

The same current is flowing in two alternating circuits. The first circuit contains only an inductor and the other contains only a capacitor. If the frequency of the $AC$ emf is increased,what will be the effect on the value of the current?

Keeping the source frequency equal to the resonating frequency of the series $LCR$ circuit,if the three elements,$L, C$ and $R$ are arranged in parallel,show that the total current in the parallel $LCR$ circuit is minimum at this frequency. Obtain the $rms$ current value in each branch of the circuit given below.
Figure shows a series $LCR$ circuit connected to a variable frequency $230\; V$ source. $L=5.0\; H, C=80\; \mu F, R=40\; \Omega$.

An alternating voltage $E = 200 \sqrt{2} \sin(100 t) \text{ V}$ is connected to a $1 \mu\text{F}$ capacitor through an $A.C.$ ammeter. The reading of the ammeter shall be: (in $\text{ mA}$)

Discuss power in an $AC$ circuit containing only a capacitor.