The initial velocity of the particle is 10 m | vedclass

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(A) The distance traveled by a particle in the $n^{th}$ second is given by the formula: $S_n = u + \frac{a}{2}(2n - 1)$.Here,the initial velocity $u =

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$1$

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(A) The distance traveled by a particle in the $n^{th}$ second is given by the formula: $S_n = u + \frac{a}{2}(2n - 1)$.Here,the initial velocity $u = 10 \ m/s$,the acceleration $a = -2 \ m/s^2$ (since it is retardation),and $n = 5$.Substituting these values into the formula:$S_5 = 10 + \frac{-2}{2}(2 	imes 5 - 1)$$S_5 = 10 - 1(10 - 1)$$S_5 = 10 - 9 = 1 \ m$.Therefore,the distance moved by the particle in the $5^{th}$ second is $1 \ m$.

The initial velocity of the particle is $10 \ m/s$ and its retardation is $2 \ m/s^2$. The distance moved by the particle in the $5^{th}$ second of its motion is .......... $m$.

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