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(D) The instantaneous current is given by $I = 6 \sin(100 \pi t + \frac{\pi}{4})$.The instantaneous voltage is given by $V = 5 \sin(100 \pi t - \frac{

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current leads the voltage by $90^{\circ}$

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(D) The instantaneous current is given by $I = 6 \sin(100 \pi t + \frac{\pi}{4})$.The instantaneous voltage is given by $V = 5 \sin(100 \pi t - \frac{\pi}{4})$.The phase of the current is $\phi_I = 100 \pi t + \frac{\pi}{4}$.The phase of the voltage is $\phi_V = 100 \pi t - \frac{\pi}{4}$.The phase difference between current and voltage is $\Delta \phi = \phi_I - \phi_V = (100 \pi t + \frac{\pi}{4}) - (100 \pi t - \frac{\pi}{4}) = \frac{\pi}{4} + \frac{\pi}{4} = \frac{\pi}{2}$.Since $\Delta \phi = \frac{\pi}{2}$ (or $90^{\circ}$) and the phase of the current is greater than the phase of the voltage,the current leads the voltage by $90^{\circ}$.

The instantaneous values of current and voltage in an $AC$ circuit are given by $I = 6 \sin(100 \pi t + \frac{\pi}{4})$ and $V = 5 \sin(100 \pi t - \frac{\pi}{4})$. Then,

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