The internal energy of one mole of a rigid di | vedclass

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(B) For a rigid diatomic gas molecule,the degrees of freedom $(f)$ are $5$ ($3$ translational and $2$ rotational).According to the law of equipartitio

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$\frac{5}{2} RT$

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(B) For a rigid diatomic gas molecule,the degrees of freedom $(f)$ are $5$ ($3$ translational and $2$ rotational).According to the law of equipartition of energy,the internal energy $(U)$ of $n$ moles of an ideal gas is given by $U = n \cdot \frac{f}{2} RT$.Given $n = 1$ mole and $f = 5$,we substitute these values into the formula:$U = 1 \cdot \frac{5}{2} RT = \frac{5}{2} RT$.Therefore,the internal energy is $\frac{5}{2} RT$.

The internal energy of one mole of a rigid diatomic gas at absolute temperature $T$ is

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