The inversion temperature T_i , (K) of hydrog | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The inversion temperature $(T_i)$ is the temperature below which a gas cools upon Joule-Thomson expansion. It is calculated using the formula: $T_

Vedclass · Accepted Answer

$220$

Vedclass · Answer

(B) The inversion temperature $(T_i)$ is the temperature below which a gas cools upon Joule-Thomson expansion. It is calculated using the formula: $T_i = \frac{2a}{bR}$. Given: $a = 0.244 \, atm \, L^2 \, mol^{-2}$ $b = 0.027 \, L \, mol^{-1}$ $R = 0.0821 \, L \, atm \, K^{-1} \, mol^{-1}$ Substituting these values into the formula: $T_i = \frac{2 	imes 0.244}{0.027 	imes 0.0821} \approx \frac{0.488}{0.0022167} \approx 220.15 \, K$. Rounding to the nearest integer,we get $220 \, K$.

The inversion temperature $T_i \, (K)$ of hydrogen is (given van der Waal's constants $a$ and $b$ are $0.244 \, atm \, L^2 \, mol^{-2}$ and $0.027 \, L \, mol^{-1}$ respectively).

Similar Questions

$CH_4$ gas is behaving non-ideally. The compressibility factor for the gas is $1.5$ at $2 \ atm$ and $400 \ K$. Calculate the molar volume for the gas in $litre$. [Given $R = 0.08 \ L \ atm \ K^{-1} \ mol^{-1}$]

Consider the equation $Z = \frac{PV}{RT}.$ Which of the following statements is correct?

Van der Waals equation for a gas is stated as,
$p = \frac{nRT}{V - nb} - a\left( \frac{n}{V} \right)^2$
This equation reduces to the perfect gas equation,$p = \frac{nRT}{V}$,when:

The deviation from the ideal gas equation $PV = nRT$ is maximum under which of the following conditions?

Which of the following formulae is used to determine the compressibility factor $(Z)$ for the measurement of deviation from ideal behavior?

Vedclass Test Series

Exam Paper Generator

Online Exam Module