The ionic conductance of the following cations in a given concentration is in the order:

Limiting molar conductivity of $CH_3COOH$ (i.e.,$\Lambda^o_{m(CH_3COOH)}$) is equal to:

When a certain conductivity cell was filled with $0.1 \ M \ KCl$,it had a resistance of $85 \ \Omega$ at $25 \ ^oC$. When the same cell was filled with an aqueous solution of $0.052 \ M$ unknown electrolyte,the resistance was $96 \ \Omega$. Calculate the molar conductivity of the unknown electrolyte at this concentration ............. $\Omega^{-1} \ cm^2 \ mol^{-1}$ (Given: Specific conductance of $0.1 \ M \ KCl = 1.29 \times 10^{-2} \ \Omega^{-1} \ cm^{-1}$)

Between $AC$ and $DC$ current,which one is used to determine the conductivity of an electrolytic solution? Why?

Why is alternating current $(AC)$ used for measuring the resistance of an electrolytic solution?

The ionic conductances of $Ba^{2+}$ and $Cl^{-}$ at infinite dilution are $127$ and $76 \ \Omega^{-1} \ cm^2 \ eq^{-1}$ respectively. The equivalent conductance of $BaCl_2$ at infinite dilution is ..... (in $.5$)