The ionic conductivity of Ba^{2+} and Cl^{-} | vedclass

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(A) According to Kohlrausch's law of independent migration of ions,the equivalent conductivity of an electrolyte at infinite dilution is the sum of th

Vedclass · Accepted Answer

$203$

Vedclass · Answer

(A) According to Kohlrausch's law of independent migration of ions,the equivalent conductivity of an electrolyte at infinite dilution is the sum of the equivalent conductivities of its constituent ions.For $BaCl_2$,the equivalent conductivity at infinite dilution is given by:$\Lambda^{\infty}_{eq}(BaCl_2) = \lambda^{\infty}_{eq}(Ba^{2+}) + \lambda^{\infty}_{eq}(Cl^{-})$Given that the ionic conductivities provided are already in terms of equivalent conductivities $(ohm^{-1} cm^2 eq^{-1})$,we simply add the values:$\Lambda^{\infty}_{eq}(BaCl_2) = 127 + 76 = 203 \ ohm^{-1} cm^2 eq^{-1}$Therefore,the correct option is $A$.

The ionic conductivity of $Ba^{2+}$ and $Cl^{-}$ at infinite dilution are $127$ and $76 \ ohm^{-1} cm^2 eq^{-1}$ respectively. The equivalent conductivity of $BaCl_2$ at infinite dilution (in $ohm^{-1} cm^2 eq^{-1}$) would be $:-$

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