The ionic radius of $Rb^{+}$ and $I^{-}$ respectively is $1.46 \ \mathring{A}$ and $2.16 \ \mathring{A}$. The geometry of $RbI$ would be similar to

  • A
    $CsCl$
  • B
    $NaCl$
  • C
    $ZnS$
  • D
    Boron-oxide

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Similar Questions

In the periodic table,going down in the fluorine group $(Group \ 17)$:

Among the ions $Mg^{2+}, O^{2-}, Al^{3+}, F^{-}, Na^{+}$ and $N^{3-}$,the ion with largest size and ion with smallest size are respectively

In which of the following options are the elements correctly arranged in the increasing order of their atomic radius?

$Al^{3+}$ has a lower ionic radius than $Mg^{2+}$ because

Of the following,the one with the largest size is:

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