The kinetic energy of an electron having de-Broglie wavelength $\lambda$ is ($h=$ Planck's constant,$m=$ mass of electron).
- A$\frac{h}{2 m \lambda}$
- B$\frac{h^2}{2 m \lambda^2}$
- C$\frac{h^2}{2 m^2 \lambda^2}$
- D$\frac{h^2}{2 m^2 \lambda}$
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