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(D) For an electron revolving in an orbit around a nucleus,the total energy $E$,kinetic energy $K.E.$,and potential energy $P.E.$ are related as follo

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Half of its $P.E.$

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(D) For an electron revolving in an orbit around a nucleus,the total energy $E$,kinetic energy $K.E.$,and potential energy $P.E.$ are related as follows:$K.E. = -E$$P.E. = 2E$From these relations,we can see that $K.E. = -\frac{1}{2} P.E.$In terms of magnitude,the kinetic energy is half of the potential energy.$|K.E.| = \frac{1}{2} |P.E.|$Therefore,the kinetic energy is half of its $P.E.$

The kinetic energy of an electron revolving around a nucleus will be

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