The kinetic energy of the electron in an orbi | vedclass

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(B) In the $CGS$ system,the electrostatic potential energy $U$ of an electron in an orbit of radius $r$ in a hydrogen atom is given by $U = -\frac{e^2

Vedclass · Accepted Answer

$\frac{e^2}{2r}$

Vedclass · Answer

(B) In the $CGS$ system,the electrostatic potential energy $U$ of an electron in an orbit of radius $r$ in a hydrogen atom is given by $U = -\frac{e^2}{r}$.According to the virial theorem for a system with a $1/r$ potential,the kinetic energy $K$ is related to the potential energy $U$ by the relation $K = -\frac{1}{2}U$.Substituting the value of $U$,we get $K = -\frac{1}{2} \left( -\frac{e^2}{r} \right) = \frac{e^2}{2r}$.

The kinetic energy of the electron in an orbit of radius $r$ in a hydrogen atom is ($e =$ electronic charge).

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