The last day of a century cannot be

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(B) century consists of $100$ years. In $100$ years,there are $76$ ordinary years and $24$ leap years.Number of odd days $= (76 	imes 1 + 24 	imes 2

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Tuesday

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(B) century consists of $100$ years. In $100$ years,there are $76$ ordinary years and $24$ leap years.Number of odd days $= (76 	imes 1 + 24 	imes 2) = 76 + 48 = 124$ days.$124 \div 7 = 17$ weeks and $5$ odd days.Therefore,the last day of the $1$st century is Friday.For $200$ years,odd days $= 5 	imes 2 = 10 \equiv 3$ odd days. The last day is Wednesday.For $300$ years,odd days $= 5 	imes 3 = 15 \equiv 1$ odd day. The last day is Monday.For $400$ years,odd days $= (5 	imes 4 + 1) = 21 \equiv 0$ odd days. The last day is Sunday.The last day of a century can only be Monday,Wednesday,Friday,or Sunday.Thus,the last day of a century cannot be Tuesday,Thursday,or Saturday.

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