The lead wires should have

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Lead wires are used to connect a power source to a load. To minimize power loss $(P = I^2R)$ and voltage drop $(V = IR)$ across the wires, the res

Vedclass · Accepted Answer

Larger diameter and low resistance

Vedclass · Answer

(A) Lead wires are used to connect a power source to a load. To minimize power loss $(P = I^2R)$ and voltage drop $(V = IR)$ across the wires, the resistance $(R)$ of the wires should be as low as possible.Since resistance is given by the formula $R = \rho \frac{L}{A}$, where $\rho$ is resistivity, $L$ is length, and $A$ is the cross-sectional area $(A = \pi r^2)$, to decrease resistance, we need to increase the cross-sectional area $(A)$.Increasing the area means increasing the diameter of the wire.Therefore, lead wires should have a larger diameter to ensure low resistance.

Similar Questions

By increasing the temperature,the specific resistance of a conductor and a semiconductor respectively

Wires $A$ and $B$ have resistivities $\rho_A$ and $\rho_B$,where $\rho_B = 2 \rho_A$,and have lengths $l_A$ and $l_B$. If the diameter of wire $B$ is twice that of $A$ and the two wires have the same resistance,then the ratio $\frac{l_B}{l_A}$ is:

$A$ cylindrical copper rod has length $L$ and resistance $R$. If it is melted and formed into another rod of length $2 L$,then the resistance will be ....... $R$.

In order to increase the resistance of a given wire of uniform cross-section to four times its value,a fraction of its length is stretched uniformly until the full length of the wire becomes $\frac{3}{2}$ times the original length. What is the value of this fraction?

Two wires are made of two different materials whose specific resistances are in the ratio $2:3$,lengths are in the ratio $3:4$,and cross-sectional areas are in the ratio $4:5$. The ratio of their resistances is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module