The least count of a stop watch is $\frac{1}{5} \text{ s}$. The time of $20$ oscillations of a pendulum is measured to be $25 \text{ s}$. The maximum percentage error in the measurement of time will be .......... $\%$

$A$ quantity $Q$ is formulated as $Q = X^{-2} Y^{\frac{3}{2}} Z^{-\frac{2}{5}}$. $X, Y$ and $Z$ are independent parameters which have fractional errors of $0.1, 0.2$ and $0.5$,respectively,in measurement. The maximum fractional error of $Q$ is:

In the expression for time period $T$ of a simple pendulum $T = 2 \pi \sqrt{\frac{l}{g}}$,if the percentage error in time period $T$ and length $l$ are $2 \%$ and $2 \%$ respectively,then the percentage error in acceleration due to gravity $g$ is equal to ......... $\%$

What is the estimation of error? Write the methods for estimation.

$A$ physical quantity $X$ is related to four measurable quantities $a$,$b$,$c$,and $d$ as $X = a^2 b^3 c^{5/2} d^{-2}$. The percentage errors in the measurement of $a$,$b$,$c$,and $d$ are $1\%$,$2\%$,$3\%$,and $4\%$ respectively. The percentage error in the measurement of quantity $X$ is: (in $\%$)

Find the relative error in $Z$,if $Z = \frac{A^{4} B^{1/3}}{C D^{3/2}}$.